x^2+2x-340=0

Solution for x^2+2x-340=0 equation:

x^2+2x-340=0

a = 1; b = 2; c = -340;
Δ = b2-4ac
Δ = 22-4·1·(-340)
Δ = 1364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1364}=\sqrt{4*341}=\sqrt{4}*\sqrt{341}=2\sqrt{341}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{341}}{2*1}=\frac{-2-2\sqrt{341}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{341}}{2*1}=\frac{-2+2\sqrt{341}}{2}
$